Please see the attached .SLDPRT.
Currently, the helical cut (Cut-Sweep4) is making 60 revolutions along its path.
I would like to change that to 1 revolution every 0.125" along its path.
For clarity, I would like the pitch to remain at 0.125" regardless of what the path length is.
Is this possible?
Thanks.
setting the pitch of a helical sweep
setting the pitch of a helical sweep
- Attachments
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- helical_cut_pitch_forum.SLDPRT
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SW 2024 SP 5.0
Windows 11
Windows 11
Re: setting the pitch of a helical sweep
You'll probably need to create an equation to set the twist value (currently 21600°) to be driven by the sum of the lengths of the path segments.
Re: setting the pitch of a helical sweep
Interesting. Good suggestion. I'll give that a try.
SW 2024 SP 5.0
Windows 11
Windows 11
Re: setting the pitch of a helical sweep
My thought was to make the part straight, using a helix so you could control the pitch. Then use the flex command to bend it into shape.
It is close, but not perfect. Maybe someone who is more familiar with the flex command (which is just about anyone who has used the flex command) could get a better result.
This solution would also need to be equation based, because the helix (in 2022 anyway) doesn't reference geometry. It is also extremely slow to rebuild, so probably not worth chasing.
It is close, but not perfect. Maybe someone who is more familiar with the flex command (which is just about anyone who has used the flex command) could get a better result.
This solution would also need to be equation based, because the helix (in 2022 anyway) doesn't reference geometry. It is also extremely slow to rebuild, so probably not worth chasing.
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